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We have 223 guests online3 Killer Chess Tactics Most Players Cannot Find |
Written by Yury Markushin |
Friday, 01 August 2014 00:00 |
Previously we offered a few interesting tactics problems such as this, this and that. Today we want to present a 3 more interesting tactical motifs that most chess players cannot find. Take a look at these problems and challenge yourself to solve it. *** Problem 1: Vaccaroni - Mazzoki, Roma, 1891
Problem 2: Janovsky - David, Paris, 1891Problem 3: Donisthorpe - Mundell, London, 1892Solve more tactics: "There Are 3 Main Problems That 95% of All Chess Players Are Facing... "You will instantly discover how you can significantly improve your game, adding hundreds of elo points without hiring an expensive chess coach or spending 5 hours a day on chess ! |
Last Updated on Friday, 01 August 2014 10:49 |
Comments
Problem 2: Bxg7+ Kxg7, Qg4+ ( if Kf6 then Nh5 is mate ) Kh8, Rxh7+ Kxh7 , f6+ Kh8 , Qxg7 mate
Problem 3: Qxe5+ ...
The solution to it is QXe5+,if fXe5 then Bg5# or if dXe5 then bc5#.
Problem 2 : f6
Problem 3 :Qxe5+
1. f6 Nxf6
2. Bxf6 Bxf6 (or gxf6)
3. Rxh7 Kg8
4. Rh8 Kxh8
5. Qh5 Kg8 (or Kg7)
6. Qh7#
As a "chesscoach" you have overlooked 2....Nh6 in the second problem? maybe you should teach your students some degree ofmodesty when facing problems that only appear simple at first glance, but are not...
1. Qxe5+!!
Now, black has 2 chices, both leading to mate in one:
1... dxe5 2. Lc5#
1... fxe5 2. Lg5#
Most solutions given to problem 2, apart from the one posted by MarkIX, do not work.
Example: solution by Dgn
1. f6 Nxf6
2. Bxf6 Bxf6
3. Qh5? is easily refuted by 3. h6, not resulting in any mate.
Another example by Supertitiz:
1. Rxh7+ Kxh7 2. f6+ does not work due to 2... g6 Even after 3. Qh5+ Nh6, white cannot instantly force mate. Then, after 4. fxe7 Qxe7 5. Bf4, black will reply 5... Rh8, and then after 6. Qxh6 Kg8, black has averted the attack. You retain pressure in exchange for a quality, but it will not result in mate.
In conclusion, MarkIX had everything right in the first place. Other solutions given seemed hopeful and strong, but are just not decisive enough.
1. Qg4+!! Bxg4 (the only move)
2. Rxh6+! gxh6 (again, the only move)
3. Bf7#. A beautiful double bishop mate.
Most solutions to problem 2 seem good, but are not forcing enough:
Solution to problem two:
1. Bxg7+! Kxg7 (forced)
2. Rxh7+!! Here black has two options, both will be explored extensively.
Option one:
2... Kf6
3. Nh5+ Kg5 (forced)
4. Qd2+ Kg4/Kh4
5. Qf4#
Option 2:
2... Kxh7
3. Qh5+ Kg7 (if 3... Nh6 then 4. f6+ Bf5 5. Bxf5+ Kg8 6. Qxh6 with a forced mate in one.)
4. f6+ Kxf6 (if 4... Bxf6 5. Qh7#)
5. Qh8+ Kg5 (if 5... Ke6 6. Qe5#)
6. Qg7+ Kh4 (if 6... Kf4 7. Qe5+ Kg4 8. h3+ Kh4 9. Qf4+ Bg4 10. Qxg4#)
7. Qh7+ Kg5 (if 7... Nh6 8. Qxh6+ Kg4 9. Qh5+ with repetition of line after move 6.)(if 7... Kg4 8. Qh5+ with repetition.)
8. Qh5+ Kf4 and then repetition of line until 10. Qxg4#
8... Kf6 9. Qe5#
1.Qxe5+ fxe5
2.Bg5#
or 1...dxe5 2.Bc5#
i like ur solutions the most all others' are ridiculous
Wrong move order, 2 Qg4+ Kxg4
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